(x^2-3x-4)/(x^2-16)

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Solution for (x^2-3x-4)/(x^2-16) equation: 


D( x )

x^2-16 = 0

x^2-16 = 0

x^2-16 = 0

1*x^2 = 16 // : 1

x^2 = 16

x^2 = 16 // ^ 1/2

abs(x) = 4

x = 4 or x = -4

x in (-oo:-4) U (-4:4) U (4:+oo)

(x^2-(3*x)-4)/(x^2-16) = 0

(x^2-3*x-4)/(x^2-16) = 0

x^2-3*x-4 = 0

x^2-3*x-4 = 0

DELTA = (-3)^2-(-4*1*4)

DELTA = 25

DELTA > 0

x = (25^(1/2)+3)/(1*2) or x = (3-25^(1/2))/(1*2)

x = 4 or x = -1

(x+1)*(x-4) = 0

((x+1)*(x-4))/(x^2-16) = 0

( x+1 )

x+1 = 0 // - 1

x = -1

( x-4 )

x-4 = 0 // + 4

x = 4

x in { 4} 

x = -1

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